## Watts to kVA calculation

The apparent power S in kilovolt-amps (kVA) is equal to the real power P in watts (W), divided by 1000 times the power factor PF:

*S*_{(kVA)} = * P*_{(W)} / (1000 × *PF*)

The apparent power S in kilovolt-amps (kVA) is equal to the real power P in watts (W), divided by 1000 times the power factor PF:

*S*_{(kVA)} = * P*_{(W)} / (1000 × *PF*)

The real power P in kilowatts (kW) is equal to the apparent power S in kilovolt-amps (kVA), times the power factor PF:

*P*_{(kW)} = * S*_{(kVA)} × *PF*

The current I in amps is equal to 1000 times the apparent power S in kilovolt-amps, divided by the voltage V in volts:

*I*_{(A)} = 1000 × *S*_{(kVA)}* */ *V*_{(V)}

The phase current I in amps (with balanced loads) is equal to 1000 times the apparent power S in kilovolt-amps, divided by the square root of 3 times the line to line RMS voltage V_{L-L} in volts:

*I*_{(A)} = 1000 × *S*_{(kVA)}* */ (*√*3 × *V*_{L-L(V)}* *)

The phase current I in amps (with balanced loads) is equal to 1000 times the apparent power S in kilovolt-amps, divided by 3 times the line to neutral RMS voltage V_{L-N} in volts:

*I*_{(A)} = 1000 × *S*_{(kVA)}* */ (3 × *V*_{L-N(V)}* *)